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7 | 7 | import java.util.HashMap;
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8 | 8 | import java.util.Map;
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9 | 9 |
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| 10 | +/**436. Find Right Interval |
| 11 | + * |
| 12 | + * Given a set of intervals, for each of the interval i, check if there exists an interval j whose start |
| 13 | + * point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. |
| 14 | + * |
| 15 | + * For any interval i, you need to store the minimum interval j's index, |
| 16 | + * which means that the interval j has the minimum start point to build the "right" relationship for interval i. |
| 17 | + * If the interval j doesn't exist, store -1 for the interval i. Finally, you need output the stored value of each interval as an array. |
| 18 | + * |
| 19 | + * Note: |
| 20 | + * |
| 21 | + * You may assume the interval's end point is always bigger than its start point. |
| 22 | + * You may assume none of these intervals have the same start point. |
| 23 | + * |
| 24 | + * Example 1: |
| 25 | + * Input: [ [1,2] ] |
| 26 | + * Output: [-1] |
| 27 | + * Explanation: There is only one interval in the collection, so it outputs -1. |
| 28 | + * |
| 29 | + * Example 2: |
| 30 | + * Input: [ [3,4], [2,3], [1,2] ] |
| 31 | + * Output: [-1, 0, 1] |
| 32 | + * Explanation: There is no satisfied "right" interval for [3,4]. |
| 33 | + * For [2,3], the interval [3,4] has minimum-"right" start point; |
| 34 | + * For [1,2], the interval [2,3] has minimum-"right" start point. |
| 35 | + * |
| 36 | + * Example 3: |
| 37 | + * Input: [ [1,4], [2,3], [3,4] ] |
| 38 | + * Output: [-1, 2, -1] |
| 39 | + * Explanation: There is no satisfied "right" interval for [1,4] and [3,4]. |
| 40 | + * For [2,3], the interval [3,4] has minimum-"right" start point. |
| 41 | + * */ |
10 | 42 |
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11 | 43 | public class _436 {
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12 | 44 |
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13 |
| - public static int[] findRightInterval(Interval[] intervals) { |
14 |
| - if (intervals == null || intervals.length == 0) { |
15 |
| - return new int[0]; |
16 |
| - } |
17 |
| - int[] result = new int[intervals.length]; |
18 |
| - result[0] = -1; |
19 |
| - Interval last = intervals[intervals.length - 1]; |
20 |
| - Interval first = intervals[0]; |
21 |
| - Map<Interval, Integer> map = new HashMap(); |
22 |
| - for (int i = 0; i < intervals.length; i++) { |
23 |
| - map.put(intervals[i], i); |
24 |
| - } |
| 45 | + public static class Solution1 { |
| 46 | + public int[] findRightInterval(Interval[] intervals) { |
| 47 | + if (intervals == null || intervals.length == 0) { |
| 48 | + return new int[0]; |
| 49 | + } |
| 50 | + int[] result = new int[intervals.length]; |
| 51 | + result[0] = -1; |
| 52 | + Interval last = intervals[intervals.length - 1]; |
| 53 | + Interval first = intervals[0]; |
| 54 | + Map<Interval, Integer> map = new HashMap(); |
| 55 | + for (int i = 0; i < intervals.length; i++) { |
| 56 | + map.put(intervals[i], i); |
| 57 | + } |
25 | 58 |
|
26 |
| - Collections.sort(Arrays.asList(intervals), (o1, o2) -> o1.start - o2.start); |
| 59 | + Collections.sort(Arrays.asList(intervals), (o1, o2) -> o1.start - o2.start); |
27 | 60 |
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28 |
| - for (int i = 1; i < intervals.length; i++) { |
29 |
| - //TODO: use binary search for the minimum start interval for interval[i-1] instead of a while loop |
30 |
| - int tmp = i - 1; |
31 |
| - int tmpI = i; |
32 |
| - while (tmpI < intervals.length && intervals[tmpI].start < intervals[tmp].end) { |
33 |
| - tmpI++; |
| 61 | + for (int i = 1; i < intervals.length; i++) { |
| 62 | + //TODO: use binary search for the minimum start interval for interval[i-1] instead of a while loop |
| 63 | + int tmp = i - 1; |
| 64 | + int tmpI = i; |
| 65 | + while (tmpI < intervals.length && intervals[tmpI].start < intervals[tmp].end) { |
| 66 | + tmpI++; |
| 67 | + } |
| 68 | + if (tmpI < intervals.length) { |
| 69 | + result[map.get(intervals[tmp])] = map.get(intervals[tmpI]); |
| 70 | + } else { |
| 71 | + result[map.get(intervals[tmp])] = -1; |
| 72 | + } |
34 | 73 | }
|
35 |
| - if (tmpI < intervals.length) { |
36 |
| - result[map.get(intervals[tmp])] = map.get(intervals[tmpI]); |
37 |
| - } else { |
38 |
| - result[map.get(intervals[tmp])] = -1; |
| 74 | + if (result[intervals.length - 1] == 0 && last.end > first.start) { |
| 75 | + result[intervals.length - 1] = -1; |
39 | 76 | }
|
| 77 | + return result; |
40 | 78 | }
|
41 |
| - if (result[intervals.length - 1] == 0 && last.end > first.start) { |
42 |
| - result[intervals.length - 1] = -1; |
43 |
| - } |
44 |
| - return result; |
45 | 79 | }
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46 | 80 |
|
47 |
| - |
48 |
| - public static void main(String... args) { |
49 |
| - Interval[] intervals = new Interval[3]; |
50 |
| -// intervals[0] = new Interval(1,4); |
51 |
| -// intervals[1] = new Interval(2,3); |
52 |
| -// intervals[2] = new Interval(3,4); |
53 |
| - |
54 |
| - intervals[0] = new Interval(3, 4); |
55 |
| - intervals[1] = new Interval(2, 3); |
56 |
| - intervals[2] = new Interval(1, 2); |
57 |
| - findRightInterval(intervals); |
58 |
| - } |
59 | 81 | }
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