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Added solution for Project Euler problem 59 #4031
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7e90f6a
Added solution for Project Euler problem 59
fpringle 3f30bb6
updating DIRECTORY.md
b5223b2
Formatting, type hints, no more evil map functions
fpringle b822714
Doctests
fpringle 32a2d4a
Added doctests for Project Euler problem 59
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""" | ||
Each character on a computer is assigned a unique code and the preferred standard is | ||
ASCII (American Standard Code for Information Interchange). | ||
For example, uppercase A = 65, asterisk (*) = 42, and lowercase k = 107. | ||
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A modern encryption method is to take a text file, convert the bytes to ASCII, then | ||
XOR each byte with a given value, taken from a secret key. The advantage with the | ||
XOR function is that using the same encryption key on the cipher text, restores | ||
the plain text; for example, 65 XOR 42 = 107, then 107 XOR 42 = 65. | ||
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For unbreakable encryption, the key is the same length as the plain text message, and | ||
the key is made up of random bytes. The user would keep the encrypted message and the | ||
encryption key in different locations, and without both "halves", it is impossible to | ||
decrypt the message. | ||
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Unfortunately, this method is impractical for most users, so the modified method is | ||
to use a password as a key. If the password is shorter than the message, which is | ||
likely, the key is repeated cyclically throughout the message. The balance for this | ||
method is using a sufficiently long password key for security, but short enough to | ||
be memorable. | ||
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Your task has been made easy, as the encryption key consists of three lower case | ||
characters. Using p059_cipher.txt (right click and 'Save Link/Target As...'), a | ||
file containing the encrypted ASCII codes, and the knowledge that the plain text | ||
must contain common English words, decrypt the message and find the sum of the ASCII | ||
values in the original text. | ||
""" | ||
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import string | ||
from itertools import cycle, product | ||
from pathlib import Path | ||
from typing import List, Optional, Set, Tuple | ||
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VALID_CHARS: str = ( | ||
string.ascii_letters + string.digits + string.punctuation + string.whitespace | ||
) | ||
LOWERCASE_INTS: List[int] = [ord(letter) for letter in string.ascii_lowercase] | ||
VALID_INTS: Set[int] = {ord(char) for char in VALID_CHARS} | ||
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COMMON_WORDS: List[str] = ["the", "be", "to", "of", "and", "in", "that", "have"] | ||
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def try_key(ciphertext: List[int], key: Tuple[int, ...]) -> Optional[str]: | ||
""" | ||
Given an encrypted message and a possible 3-character key, decrypt the message. | ||
If the decrypted message contains a invalid character, i.e. not an ASCII letter, | ||
a digit, punctuation or whitespace, then we know the key is incorrect, so return | ||
None. | ||
>>> try_key([0, 17, 20, 4, 27], (104, 116, 120)) | ||
'hello' | ||
>>> try_key([68, 10, 300, 4, 27], (104, 116, 120)) is None | ||
True | ||
""" | ||
decoded: str = "" | ||
keychar: int | ||
cipherchar: int | ||
decodedchar: int | ||
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for keychar, cipherchar in zip(cycle(key), ciphertext): | ||
decodedchar = cipherchar ^ keychar | ||
if decodedchar not in VALID_INTS: | ||
return None | ||
decoded += chr(decodedchar) | ||
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return decoded | ||
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def filter_valid_chars(ciphertext: List[int]) -> List[str]: | ||
""" | ||
Given an encrypted message, test all 3-character strings to try and find the | ||
key. Return a list of the possible decrypted messages. | ||
""" | ||
possibles: List[str] = [] | ||
for key in product(LOWERCASE_INTS, repeat=3): | ||
encoded = try_key(ciphertext, key) | ||
if encoded is not None: | ||
possibles.append(encoded) | ||
return possibles | ||
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def filter_common_word(possibles: List[str], common_word: str) -> List[str]: | ||
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""" | ||
Given a list of possible decoded messages, narrow down the possibilities | ||
for checking for the presence of a specified common word. Only decoded messages | ||
containing common_word will be returned. | ||
""" | ||
return [possible for possible in possibles if common_word in possible] | ||
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def solution() -> int: | ||
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""" | ||
Test the ciphertext against all possible 3-character keys, then narrow down the | ||
possibilities by filtering using common words until there's only one possible | ||
decoded message. | ||
""" | ||
ciphertext: List[int] | ||
possibles: List[str] | ||
common_word: str | ||
decoded_text: str | ||
data: str = ( | ||
Path(__file__).parent.joinpath("p059_cipher.txt").read_text(encoding="utf-8") | ||
) | ||
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ciphertext = [int(number) for number in data.strip().split(",")] | ||
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possibles = filter_valid_chars(ciphertext) | ||
for common_word in COMMON_WORDS: | ||
possibles = filter_common_word(possibles, common_word) | ||
if len(possibles) == 1: | ||
break | ||
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decoded_text = possibles[0] | ||
return sum([ord(char) for char in decoded_text]) | ||
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if __name__ == "__main__": | ||
print(f"{solution() = }") |
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