Skip to content

solution: Project Euler Problem 28 #1198

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 2 commits into from
Oct 16, 2022
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
53 changes: 53 additions & 0 deletions Project-Euler/Problem028.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,53 @@
/**
* Problem 28 - Number spiral diagonals
*
* @see {@link https://projecteuler.net/problem=28}
*
* Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:
*
* 21 22 23 24 25
* 20 07 08 09 10
* 19 06 01 02 11
* 18 05 04 03 12
* 17 16 15 14 13
*
* It can be verified that the sum of the numbers on the diagonals is 101.
* What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way?
*
* @author ddaniel27
*/

function problem28 (dim) {
if (dim % 2 === 0) {
throw new Error('Dimension must be odd')
}
if (dim < 1) {
throw new Error('Dimension must be positive')
}

let result = 1
for (let i = 3; i <= dim; i += 2) {
/**
* Adding more dimensions to the matrix, we will find at the top-right corner the follow sequence:
* 01, 09, 25, 49, 81, 121, 169, ...
* So this can be expressed as:
* i^2, where i is all odd numbers
*
* Also, we can know which numbers are in each corner dimension
* Just develop the sequence counter clockwise from top-right corner like this:
* First corner: i^2
* Second corner: i^2 - (i - 1) | The "i - 1" is the distance between corners in each dimension
* Third corner: i^2 - 2 * (i - 1)
* Fourth corner: i^2 - 3 * (i - 1)
*
* Doing the sum of each corner and simplifing, we found that the result for each dimension is:
* sumDim = 4 * i^2 + 6 * (1 - i)
*
* In this case I skip the 1x1 dim matrix because is trivial, that's why I start in a 3x3 matrix
*/
result += (4 * i * i) + 6 * (1 - i) // Calculate sum of each dimension corner
Copy link
Collaborator

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Please add a more helpful comment explaining how you arrived at this formula.

Copy link
Contributor Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Explanation added

}
return result
}

export { problem28 }
17 changes: 17 additions & 0 deletions Project-Euler/test/Problem028.test.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
import { problem28 } from '../Problem028.js'

describe('checking number spiral diagonals', () => {
it('should be invalid input if number is negative', () => {
expect(() => problem28(-3)).toThrowError('Dimension must be positive')
})
it('should be invalid input if number is not odd', () => {
expect(() => problem28(4)).toThrowError('Dimension must be odd')
})
test('if the number is equal to 5 result should be 101', () => {
expect(problem28(5)).toBe(101)
})
// Project Euler Condition Check
test('if the number is equal to 1001 result should be 669171001', () => {
expect(problem28(1001)).toBe(669171001)
})
})