Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.
Input: s = 'Here's a string of words'
Output: 'sdrow fo gnirts a s'ereH'Input: s = 'Superklok Labs'
Output: 'sbaL kolkrepuS'1 <= s.length <= 5 * 10⁴scontains printable ASCII characters.sdoes not contain any leading or trailing spaces.- There is at least one word in
s. - All the words in
sare separated by a single space.
const reverseWords = (s) => {
return s.split(' ').map((w) => w.split('')
.reverse()
.join(''))
.join(' ');
};I've written a function expression, using ES6 syntax, that is defined by an anonymous function that accepts s as a string of words.
Within the anonymous function, the string s is split into an array of string words everywhere there is a space ' ' by using the string prototype split method.
The array prototype map method is then applied to the array that was returned by the split method. The string words w in the array are then split into their own arrays of string characters using the string prototype split method at ''.
The string character arrays are then reversed using the array prototype reverse method. The newly reversed arrays are then joined together to form words w again, and this process is effectuated for each word from the array derived from s.
Once the array prototype map method is complete, the reversed words are then joined into a string using the array prototype join method that adds a space ' ' between each reversed word.