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| 1 | +/* |
| 2 | +Set Matrix Zeroes |
| 3 | +https://leetcode.com/problems/set-matrix-zeroes/ |
| 4 | +
|
| 5 | +Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place. |
| 6 | +
|
| 7 | +Example 1: |
| 8 | +
|
| 9 | +Input: |
| 10 | +[ |
| 11 | + [1,1,1], |
| 12 | + [1,0,1], |
| 13 | + [1,1,1] |
| 14 | +] |
| 15 | +Output: |
| 16 | +[ |
| 17 | + [1,0,1], |
| 18 | + [0,0,0], |
| 19 | + [1,0,1] |
| 20 | +] |
| 21 | +Example 2: |
| 22 | +
|
| 23 | +Input: |
| 24 | +[ |
| 25 | + [0,1,2,0], |
| 26 | + [3,4,5,2], |
| 27 | + [1,3,1,5] |
| 28 | +] |
| 29 | +Output: |
| 30 | +[ |
| 31 | + [0,0,0,0], |
| 32 | + [0,4,5,0], |
| 33 | + [0,3,1,0] |
| 34 | +] |
| 35 | +Follow up: |
| 36 | +
|
| 37 | +A straight forward solution using O(mn) space is probably a bad idea. |
| 38 | +A simple improvement uses O(m + n) space, but still not the best solution. |
| 39 | +Could you devise a constant space solution? |
| 40 | +*/ |
| 41 | + |
| 42 | +/** |
| 43 | + * @param {number[][]} matrix |
| 44 | + * @return {void} Do not return anything, modify matrix in-place instead. |
| 45 | + */ |
| 46 | +var setZeroes = function(matrix) { |
| 47 | + if(matrix.length === 0) |
| 48 | + return; |
| 49 | + |
| 50 | + var pivotRow = -1; |
| 51 | + var pivotCol = -1; |
| 52 | + var iterRow = 0; |
| 53 | + var iterCol = 0; |
| 54 | + var found = false; |
| 55 | + |
| 56 | + // Find a pivot |
| 57 | + while(!found && iterRow < matrix.length) { |
| 58 | + iterCol = 0; |
| 59 | + while(!found && iterCol < matrix[0].length) { |
| 60 | + if(matrix[iterRow][iterCol] === 0) { |
| 61 | + found = true |
| 62 | + pivotRow = iterRow; |
| 63 | + pivotCol = iterCol; |
| 64 | + } |
| 65 | + iterCol++; |
| 66 | + } |
| 67 | + iterRow++; |
| 68 | + } |
| 69 | + |
| 70 | + if (!found) |
| 71 | + return; |
| 72 | + |
| 73 | + // Update the Column value |
| 74 | + for(var i = 0; i < matrix.length; i++) { |
| 75 | + if(i == pivotRow) |
| 76 | + continue |
| 77 | + for(var j = 0; j < matrix[0].length; j++) { |
| 78 | + if(j == pivotCol) |
| 79 | + continue; |
| 80 | + if(matrix[i][j] === 0) { |
| 81 | + matrix[i][pivotCol] = 0; |
| 82 | + matrix[pivotRow][j] = 0; |
| 83 | + } |
| 84 | + } |
| 85 | + } |
| 86 | + |
| 87 | + for(var i = 0; i < matrix.length; i++) |
| 88 | + if(matrix[i][pivotCol] === 0 && i !== pivotRow) |
| 89 | + fillRow(matrix, i); |
| 90 | + |
| 91 | + for(var i = 0; i < matrix[0].length; i++) |
| 92 | + if(matrix[pivotRow][i] === 0 && i !== pivotCol) |
| 93 | + fillCol(matrix, i); |
| 94 | + |
| 95 | + fillCol(matrix, pivotCol); |
| 96 | + fillRow(matrix, pivotRow); |
| 97 | +}; |
| 98 | + |
| 99 | +var fillRow = function(matrix, row) { |
| 100 | + for(var i = 0; i < matrix[0].length; i++) |
| 101 | + matrix[row][i] = 0; |
| 102 | +} |
| 103 | + |
| 104 | +var fillCol = function(matrix, col) { |
| 105 | + for(var i = 0; i < matrix.length; i++) |
| 106 | + matrix[i][col] = 0; |
| 107 | +} |
| 108 | + |
| 109 | +var main = function() { |
| 110 | + console.log(setZeroes([[1,1,1],[1,0,1],[1,1,1]])); |
| 111 | +} |
| 112 | + |
| 113 | +module.exports.main = main; |
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