added solution 7 for problem_01 (TheAlgorithms#1416)

* added solution 7 for problem_01

* added solution 5 for problem_02

Author: suadjelili

project_euler/problem_01/sol7.py

@@ -0,0 +1,32 @@
+"""
+Problem Statement:
+If we list all the natural numbers below 10 that are multiples of 3 or 5,
+we get 3,5,6 and 9. The sum of these multiples is 23.
+Find the sum of all the multiples of 3 or 5 below N.
+"""
+
+
+def solution(n):
+    """Returns the sum of all the multiples of 3 or 5 below n.
+
+    >>> solution(3)
+    0
+    >>> solution(4)
+    3
+    >>> solution(10)
+    23
+    >>> solution(600)
+    83700
+    """
+
+    result = 0
+    for i in range(n):
+        if i % 3 == 0:
+            result += i
+        elif i % 5 == 0:
+            result += i
+    return result
+
+
+if __name__ == "__main__":
+    print(solution(int(input().strip())))

project_euler/problem_02/sol5.py

@@ -0,0 +1,46 @@
+"""
+Problem:
+Each new term in the Fibonacci sequence is generated by adding the previous two
+terms. By starting with 1 and 2, the first 10 terms will be:
+
+    1,2,3,5,8,13,21,34,55,89,..
+
+By considering the terms in the Fibonacci sequence whose values do not exceed
+n, find the sum of the even-valued terms. e.g. for n=10, we have {2,8}, sum is
+10.
+"""
+
+
+def solution(n):
+    """Returns the sum of all fibonacci sequence even elements that are lower
+    or equals to n.
+
+    >>> solution(10)
+    10
+    >>> solution(15)
+    10
+    >>> solution(2)
+    2
+    >>> solution(1)
+    0
+    >>> solution(34)
+    44
+    """
+
+    a = [0,1]
+    i = 0
+    while a[i] <= n:
+        a.append(a[i] + a[i+1])
+        if a[i+2] > n:
+            break
+        i += 1
+    sum = 0
+    for j in range(len(a) - 1):
+        if a[j] % 2 == 0:
+            sum += a[j]
+
+    return sum
+
+
+if __name__ == "__main__":
+    print(solution(int(input().strip())))