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Practise Programs/10cubeofnousingwhile.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    int n,no=1;
+    cout<<"Enter how many numbers cube you want: "<<endl;
+    cin>>n;
+    while(no<=n)
+    {
+        cout<<"Cube of "<<no<<" = "<<no*no*no<<endl;
+        no++;
+    }
+
+return 0;
+}

Practise Programs/11evennousingwhile.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    long long int n,no=2;
+    cout<<"From 2 to how many numbers do you want even numbers : "<<endl;
+    cin>>n;
+    cout<<"List of even numbers from 2 to "<<n<<" :";
+    while(no<=n)
+    {
+        cout<<no<<endl;
+        no=no+2;
+    }
+
+return 0;
+}

Practise Programs/12fibonacciserieswhile.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    long long int a,b,c,n;
+    a=0; b=1;
+    cout<<"Enter number of terms (n) = ";
+    cin>>n;
+    cout<<"Fibonacci series is "<<endl;
+    if(n==1){
+        cout<<"0 ";
+    }else if(n==2){
+        cout<<a<<" "<<b<<" ";
+    }else{
+        cout<<a<<" "<<b<<" ";
+        long int count=3;
+        while(count<=n)
+        {
+            c=a+b;
+            cout<<c<<" ";
+            a=b;
+            b=c;
+            count++;
+        }
+    }
+return 0;
+}

Practise Programs/13palindromewhile.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    long int num,z,rev=0,rem;
+    cout<<"Enter a number = "<<endl;
+    cin>>num;
+    z=num;
+    while(num>0)
+    {
+        rem=num%10;
+        num=num/10;
+        rev=(rev*10)+rem;
+    }
+    if(rev==z){
+        cout<<"Given number is Palindrome";
+    }else{
+        cout<<"Given number is not Palindrome";
+    }
+
+return 0;
+}

Practise Programs/14tablesusingdowhile.cpp

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+#include<iostream>
+#include<iomanip>
+using namespace std;
+
+int main()
+{
+    long long int num,i=1,prod;
+    cout<<"Enter number who's table you want : "<<endl;
+    cin>>num;
+    cout<<"Table of "<<num<<" :0"<<endl;
+    do{
+        prod = num * i;
+        cout<<num<<" X "<<setw(2)<<i<<" = "<<prod<<endl;
+        i = i+1;
+    }while(i<=10);
+    cout<<"End of table";
+
+return 0;
+}

Practise Programs/15averageforloop.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    int n;
+    long int num,sum=0;
+    cout<<"Enter how many number of terms you want to enter: "<<endl;
+    cin>>n;
+    cout<<"Enter numbers now :"<<endl;
+    for(int i=0; i<n; i++)
+    {
+        cin>>num;
+        sum = sum + num;
+    }
+    float avg = float(sum)/n;
+    cout<<"Average = "<<avg<<endl;
+
+return 0;
+}

Practise Programs/16findsumofseriesfor.cpp

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+#include<iostream>
+#include<math.h>
+using namespace std;
+
+int main()
+{
+    int n;
+    float x, sum=0.0;
+    cout<<"Enter how many terms : "<<endl;
+    cin>>n;
+    cout<<"Enter the value of x : "<<endl;
+    cin>>x;
+    float z=x/(x+1);
+    for(int i=1;i<=n;i++)
+    {
+        sum=sum+pow(z,i)*1/i;
+    }
+    cout<<"Sum of Series = "<<sum;
+
+return 0;
+}

Practise Programs/17patternnestedloop.cpp

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+//You can see explanation of program in last of the program see its important
+#include<iostream>
+using namespace std;
+
+int main()
+{
+    int n;
+    cout<<"Enter how many lines : ";
+    cin>>n;
+    for(int i=1;i<=n;i++)
+    {
+        for(int j=1;j<=i;j++)
+        {
+            cout<<i<<" "; // if you print j here then series will be 1\n 1 2\n 1 2 3\n 1 2 3 4 like this
+        }
+        cout<<endl;
+    }
+
+return 0;
+}
+
+/*
+On execution we input ythe number of lines n (say 4).
+In this program the inner j loop is nested inside the outer i loop.
+For each value of variable i  of outer loop, the inner loop will be executed completely.
+For 1st iteration of outer loop, the inner loop will be executed completely.
+For 1st iteration of outer loop, the i is initialized to 1 and inner loop is executed once as the condition (j<=i) ,
+is satisfied only once, thus prints the value of i (i.e. 1) once.
+the statement cout<<"\n" must be outside the inner loop and inside the outer loop in order to produce exactly one
+line for each iteration of outer loop.
+On second iteration(pass) of outer loop, when i=2 then inner loop executes 2 times and thus displaying value of i (i.e 2)
+2 times and process will continue until the condition in the loop becomes false.
+*/

Practise Programs/18operatorsandswitch.cpp

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+//You can see the use of break statement also here
+#include<iostream>
+using namespace std;
+
+int main()
+{
+    long long int a,b,operation;
+    cout<<"Enter two numbers :"<<endl;;
+    cin>>a>>b;
+    cout<<"1. Addition"<<endl;
+    cout<<"2. Subtraction"<<endl;
+    cout<<"3. Multiplication"<<endl;
+    cout<<"4. Division"<<endl;
+    cout<<"5. Modulus"<<endl;
+    cout<<"Select appropriate number for appropriate operation :"<<endl; 
+    int choice;    
+    cin>>choice;
+    switch(choice)
+    {
+        case 1: 
+        operation=a+b;
+        cout<<" Addition = "<<operation;
+        break;
+        case 2: 
+        operation=a-b;
+        cout<<" Subtraction = "<<operation;
+        break;
+        case 3: 
+        operation=a*b;
+        cout<<" Multiplication = "<<operation;
+        break;
+        case 4: 
+        operation=a/b;
+        cout<<" Division = "<<operation;
+        break;
+        case 5: 
+        operation=a%b;
+        cout<<" Modulus = "<<operation;
+        break;
+        default:
+        cout<<"Invalid Choice";
+    }   
+
+return 0;
+}

Practise Programs/19continueillegaldivisor.cpp

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+#include<iostream>
+using namespace std;
+
+int main()
+{
+    int a,b;
+    char ch;
+    do{
+        cout<<"Enter Divident"<<endl;
+        cin>>a;
+        cout<<"Enter Divisor"<<endl;
+        cin>>b;
+        if(b==0)
+        {
+            cout<<"Illegal Divisor"<<endl;
+            continue;
+        }
+        cout<<"Quotient =\t"<<a/b<<endl;
+        cout<<"Remainder =\t"<<a%b<<endl;
+        cout<<"Want to Continue ? (y/n):";
+        cin>>ch;
+    } while(ch=='Y' || ch=='y');
+
+return 0;
+}

Practise Programs/20factorialusingfunction.cpp

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+//Lets see functional (recursion) appproach for this problem:
+
+#include<iostream>
+using namespace std;
+
+int main()
+{
+    long long int fact(int);
+    int num;
+    cout<<"Enter a number who 's factorial you want : "<<endl;
+    cin>>num;
+    cout<<"Factorial = "<<fact(num);
+
+return 0;
+}
+
+long long int fact(int x)
+{
+    long long int prod = 1;
+    if(x==0 || x==1)
+    {
+        prod = 1;
+    }else
+    {
+        for(int i=2; i<=x; i++)
+        {
+            prod = x *fact(x-1);
+        }
+    }
+    return (prod);
+    
+}
+
+
+
+
+// It is a iterative approach to solve this problem
+// #include<iostream>
+// using namespace std;
+
+// int main()
+// {
+//     long long int n,fact=1;
+//     cout<<"Enter number who's factorial you want"<<endl;
+//     cin>>n;
+//     for(int i=1;i<=n;i++)
+//     {
+//         fact=fact*i;
+//     }
+//     cout<<"Factorial of number "<<n<<" = "<<fact;
+
+// return 0;
+// }