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Create Check-if-the-Sentence-is-Pangram.py
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class Solution:
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def checkIfPangram(self, sentence: str) -> bool:
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letter_counter = {}
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for letter in sentence:
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if letter in letter_counter:
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letter_counter[letter] += 1
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else:
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letter_counter[letter] = 1
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return len(letter_counter.keys()) == 26

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